Aspire Faculty ID #17903 · Topic: JEE Main 2026 (21 January Morning Shift) · Just now
JEE Main 2026 (21 January Morning Shift)

The sum of all the roots of the equation $(x - 1)^2 - 5|x - 1| + 6 = 0$, is:

Solution

Let $|x - 1| = t$

$t^2 - 5t + 6 = 0$

$t = 2$ & $t = 3$

$|x - 1| = 2$ & $|x - 1| = 3$

$x - 1 = \pm 2,; x - 1 = \pm 3$

$x = 3, -1, 4, -2$

Sum of roots $= 3 + (-1) + 4 + (-2) = 4$

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