Aspire Faculty ID #17925 · Topic: JEE Main 2026 (21 January Evening Shift) · Just now
JEE Main 2026 (21 January Evening Shift)

Let $y = y(x)$ be the solution of differential equation $\sec x \frac{dy}{dx} - 2y = 2 + 3\sin x$, $x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, $y(0) = -\frac{7}{4}$. Then $y\left(\frac{\pi}{6}\right)$ is equal to:

Solution

$\frac{dy}{dx} - 2y\cos x = 2\cos x + 3\sin x \cos x$

$I.F. = e^{-2\sin x}$

$e^{-2\sin x}y = \int e^{-2\sin x}(3\sin x \cos x + 2\cos x),dx$

$= e^{-2\sin x}\left(-\frac{3}{2}\sin x - \frac{7}{4}\right) + C$

$\Rightarrow y = -\frac{3}{2}\sin x - \frac{7}{4} + Ce^{2\sin x}$

$y(0) = -\frac{7}{4} \Rightarrow C = 0$

$y\left(\frac{\pi}{6}\right) = -\frac{3}{2}\cdot\frac{1}{2} - \frac{7}{4} = -\frac{5}{2}$

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