Aspire Faculty ID #17926 · Topic: JEE Main 2026 (21 January Evening Shift) · Just now
JEE Main 2026 (21 January Evening Shift)

Let $A = {2,3,5,7,9}$. Let $R$ be the relation on $A$ defined by $xRy$ if and only if $2x \le 3y$. Let $\ell$ be the number of elements in $R$, and $m$ be the minimum number of elements required to be added in $R$ to make it a symmetric relation. Then $\ell + m$ is equal to:

Solution

$A = {2,3,5,7,9}$

$y \ge \frac{2x}{3}$

$x = 2 \Rightarrow y = 2,3,5,7,9$

$x = 3 \Rightarrow y = 2,3,5,7,9$

$x = 5 \Rightarrow y = 5,7,9$

$x = 7 \Rightarrow y = 5,7,9$

$x = 9 \Rightarrow y = 7,9$

$\ell = 18$

To make symmetric, elements to be added:

${(5,2), (7,2), (9,2), (5,3), (7,3), (9,3), (9,5)}$

$m = 7$

$\ell + m = 25$

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