Aspire Faculty ID #18008 · Topic: JEE Main 2026 (23 January Morning Shift) · Just now
JEE Main 2026 (23 January Morning Shift)

Let $f$ be a twice differentiable non-negative function such that

$(f(x))^2 = 25 + \int_0^x \big((f(t))^2 + (f'(t))^2\big),dt$.

Then the mean of $f(\log 1),; f(\log 2),; \ldots,; f(\log 625)$ is equal to ______.

Solution

$2f(x)f'(x) = f(x) + (f'(x))^2$

$\Rightarrow (f(x) - f'(x))^2 = 0$

$\Rightarrow f(x) = f'(x)$

$\Rightarrow \ln f(x) = x + c \Rightarrow f(x) = ce^x$

$f(0) = 5 \Rightarrow f(x) = 5e^x$

Mean

$= \frac{f(\ln 1) + f(\ln 2) + \cdots + f(\ln 625)}{625}$

$= \frac{5(1 + 2 + \cdots + 625)}{625}$

$= \frac{5 \cdot \frac{625 \cdot 626}{2}}{625} = 1565$

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