Aspire Faculty ID #18063 · Topic: JEE Main 2026 (24 January Evening Shift) · Just now
JEE Main 2026 (24 January Evening Shift)

Let the angles made with the positive $x$-axis by two straight lines drawn from the point $P(2, 3)$ and meeting the line $x + y = 6$ at a distance $ \sqrt{\frac{2}{3}} $ from the point $P$ be $ \theta_1 $ and $ \theta_2 $. Then the value of $ (\theta_1 + \theta_2) $ is:

Solution



Let $Q$ is $ \left( \sqrt{\frac{2}{3}} \cos\theta + 2,; \sqrt{\frac{2}{3}} \sin\theta + 3 \right) $

so, $ x + y = 6 $

$ \sqrt{\frac{2}{3}} (\cos\theta + \sin\theta) + 5 = 6 $

$ \sin\theta + \cos\theta = \sqrt{\frac{3}{2}} $

$ 1 + \sin 2\theta = \frac{3}{2} $

$ \sin 2\theta = \frac{1}{2} $

$ 2\theta = \frac{\pi}{6},; \frac{5\pi}{6} $

$ \theta = \frac{\pi}{12},; \frac{5\pi}{12} $

So $ \theta_1 + \theta_2 = \frac{\pi}{2} $

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