Aspire Faculty ID #18134 · Topic: JEE Main 2026 (28 January Evening Shift) · Just now
JEE Main 2026 (28 January Evening Shift)

If the distance of the point $ P(43, \alpha, \beta) $ from the line $ \vec{r} = 4\hat{i} - \hat{k} + \mu(2\hat{i} + 3\hat{k}),; \mu \in \mathbb{R} $ along a line with direction ratios $ 3, -1, 0 $ is $ 13\sqrt{10} $, then $ \alpha^2 + \beta^2 $ is equal to ______

Solution

$ \frac{x - 43}{3} = \frac{y - \alpha}{-1} = \frac{z - \beta}{0} $

$ \Rightarrow P(43 + 3\lambda,; \alpha - \lambda,; \beta) $

$ \Rightarrow \alpha = 13,; \beta = 1 $

$ \Rightarrow \alpha^2 + \beta^2 = 170 $

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