Aspire Faculty ID #18297 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

Let $P={\theta;\ \sin\theta - \cos\theta = \sqrt{2}\cos\theta}$ and $Q={\theta;\ \sin\theta + \cos\theta = \sqrt{2}\sin\theta}$ be two sets. Then,

Solution

For $P$ $ \sin\theta - \cos\theta = \sqrt{2}\cos\theta $ $ \Rightarrow \tan\theta - 1 = \sqrt{2} $ $ \Rightarrow \tan\theta = \sqrt{2} + 1 $ For $Q$ $ \sin\theta + \cos\theta = \sqrt{2}\sin\theta $ $ \Rightarrow 1 + \cot\theta = \sqrt{2} $ $ \Rightarrow \cot\theta = \sqrt{2} - 1 $ $ \Rightarrow \tan\theta = \sqrt{2} + 1 $ $ \therefore P = Q $

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