The number of words with or without meaning which can be made using all the letters of the word AGAIN. If these words are written as in a dictionary, then the $50$th word will be

Letters: A, A, G, I, N Words starting with A: $ \frac{4!}{2!}=12 $ Starting with G: $ \frac{4!}{2!}=12 $ Starting with I: $ \frac{4!}{2!}=12 $ Total till I: $12+12+12=36$ Next start with N Remaining: A, A, G, I Arrangements: $ \frac{4!}{2!}=12 $ So positions $37$ to $48$ $49^{th}$ word = NAAGI $50^{th}$ word = NAAIG