Aspire Faculty ID #18331 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

Differentiate y = sin⁻¹((1 - x²)/(1 + x²)), 0 < x < 1 with respect to x.

Solution

Put $x=\tan \theta$ $ \Rightarrow \frac{1-x^2}{1+x^2}=\frac{1-\tan^2\theta}{1+\tan^2\theta}=\cos 2\theta $ So, $ y=\sin^{-1}(\cos 2\theta) $ Now important step (range use): Since $0
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