Aspire Faculty ID #18352 · Topic: AMU MCA 2016 · Just now
AMU MCA 2016

$\int \sqrt{16 - 9x^2} , dx$ equals

Solution

Use standard formula: $\int \sqrt{a^2 - b^2 x^2} dx = \frac{x}{2}\sqrt{a^2 - b^2 x^2} + \frac{a^2}{2b}\sin^{-1}\left(\frac{bx}{a}\right) + C$ Here $a=4,\ b=3$ $= \frac{x}{2}\sqrt{16 - 9x^2} + \frac{16}{6}\sin^{-1}\left(\frac{3x}{4}\right)$ $= \frac{x}{2}\sqrt{16 - 9x^2} + \frac{8}{3}\sin^{-1}\left(\frac{3x}{4}\right) + C$

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