Aspire Faculty ID #18355 · Topic: AMU MCA 2016 · Just now
AMU MCA 2016

The function $f(x)=\cos^2 x$ is strictly decreasing on

Solution

$f'(x)=2\cos x(-\sin x)=-\sin 2x$ On $(0,\frac{\pi}{2})$, $\sin 2x > 0 \Rightarrow f'(x)<0$ So decreasing on $(0,\frac{\pi}{2})$

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