Aspire Faculty ID #18717 · Topic: UGC NET Computer Science Sep 2022 (Paper II) · Just now
UGC NET Computer Science Sep 2022 (Paper II)

Consider a logic gate circuit, with 8 input lines $(D_0,D_1,\ldots,D_7)$ and 3 output lines $(A_0,A_1,A_2)$ specified by following operations

$A_2=D_4+D_5+D_6+D_7$

$A_1=D_2+D_3+D_6+D_7$

$A_0=D_1+D_3+D_5+D_0$

Where $+$ indicates logical OR operation. This circuit is

Solution

In an octal to binary encoder, there are $8$ input lines and $3$ output lines.

The outputs represent binary form of input lines $D_0$ to $D_7$.

Standard equations are:

$A_2=D_4+D_5+D_6+D_7$

$A_1=D_2+D_3+D_6+D_7$

$A_0=D_1+D_3+D_5+D_7$

So, the given circuit represents an Octal to Binary encoder.

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