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UGC NET Computer Science Sep 2022 (Paper II)

A $3000\ km$ long trunk operates at $1.536\ mbps$ and is used to transmit $64$ bytes frames and uses sliding window protocol. The propagation speed is $6\mu sec/km$

The maximum achievable throughput is

Solution

Efficiency of the system is:

$\eta=0.578$

Given data rate is:

$1.536\ Mbps$

Maximum achievable throughput is:

$Throughput=\eta\times \text{Data rate}$

$Throughput=0.578\times1.536$

$Throughput=0.887\ Mbps$

Therefore, the maximum achievable throughput is $0.887\ Mbps$.

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