What is the output of following C program?

#include <stdio.h>

main()

{

    int i, j, x = 0;

    for (i = 0; i < 5; ++i)

        for (j = 0; j < i; ++j)

        {

            x += (i + j - 1);

            break;

        }

    printf("%d", x);

}

Outer loop runs for:

$i=0,1,2,3,4$

Inner loop runs only when $j<i$.

But inside inner loop, there is a $break$ statement, so inner loop executes only one time for each valid value of $i$.

For $i=0$:

$j<0$ is false, so inner loop does not execute.

For $i=1$:

$x=x+(1+0-1)=0+0=0$

For $i=2$:

$x=x+(2+0-1)=0+1=1$

For $i=3$:

$x=x+(3+0-1)=1+2=3$

For $i=4$:

$x=x+(4+0-1)=3+3=6$

So, final value of $x$ is:

$x=6$