Aspire Faculty ID #19048 · Topic: UGC NET Computer Science Dec 2019 (Paper II) · Just now
UGC NET Computer Science Dec 2019 (Paper II)

In a B-Tree, each node represents a disk block. Suppose one block holds $8192$ bytes. Each key uses $32$ bytes. In a B-tree of order $M$ there are $M-1$ keys. Since each branch is on another disk block, we assume a branch is of $4$ bytes. The total memory requirement for a non-leaf node is:

Solution

In a B-tree of order $M$:

Number of keys $=M-1$

Memory used by keys:

$(M-1)\times 32=32M-32$

Number of branches in non-leaf node $=M$

Memory used by branches:

$M\times 4=4M$

Total memory requirement:

$(32M-32)+4M$

$=36M-32$

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