Aspire Faculty ID #3636 · Topic: NIMCET 2012 · Just now
NIMCET 2012

The equation of the plane passing through the point $(1,2,3)$ and having the normal vector $N = 3\mathbf{i} - \mathbf{j} + 2\mathbf{k}$ is:

Solution

Equation of plane with normal $(a,b,c)$ passing through $(x_1, y_1, z_1)$ is: 
$a(x - x_1) + b(y - y_1) + c(z - z_1) = 0$ 

Here: $a = 3; b = -1; c = 2$ 
$(x_1, y_1, z_1) = (1,2,3)$ 

So: $3(x - 1) - 1(y - 2) + 2(z - 3) = 0$ 
Expand: $3x - 3 - y + 2 + 2z - 6 = 0$ 
Combine constants: $3x - y + 2z - 7 = 0$ 
$3x - y + 2z = 7$ 
Thus the correct answer is: $3x - y + 2z = 7$

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