Aspire Faculty ID #4271 · Topic: NIMCET 2017 · Just now
NIMCET 2017

The mean and variance of a random variable X having binomial distribution are 4 and 2 respectively. The P(X = 1) is

Solution

np = 4

npq = 2

q = 1/2, p = 1/2, n = 8

p(X = 1) = 8C1 (1/2)(1/2)7

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