Aspire Faculty ID #4308 · Topic: NIMCET 2017 · Just now
NIMCET 2017

The solution of (ex + 1) y dy = (y + 1) ex dx is

Solution

Question: Solve $(e^x+1)\,y\,dy=(y+1)\,e^x\,dx$.

Solution:

Separate: $\dfrac{y}{y+1}\,dy=\dfrac{e^x}{e^x+1}\,dx$

Integrate: $y-\ln(y+1)=\ln(e^x+1)+C$

Answer (implicit): $\boxed{\,y-\ln(1+y)=\ln(1+e^x)+C\,}$

Equivalently: $\dfrac{e^{y}}{y+1}=K(1+e^x)$.

Answer : $e^y=k(y+1)(1+e^x)$

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