Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET
Aspire Study - Best NIMCET Coaching

🎯 Crack NIMCET with Aspire Study

🔹 India's Most Trusted MCA Coaching
💻 Live + Recorded Classes | 👨‍🏫 Expert Faculty
📝 All India Test Series | 🎯 Personal Mentorship

🥈 NIMCET AIR 2: Ayush Garg

🚀 Join Aspire Now

📂 Aspire Study Library

Question Id : 12302 | Context : JEE Main 6 September 2020 (Evening)
For a suitably chosen real constant a, let afunction, $f:R - \left\{ { - a} \right\} \to R$ be defined by$f(x) = {{a - x} \over {a + x}}$. Further suppose that for any realnumber $x \ne - a$ and $f(x) \ne - a$, (fof)(x) = x. Then $f\left( { - {1 \over 2}} \right)$ is equal to :

Aspire Study Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More
📲
Ask Your Question or Put Your Review.

loading...