Question Id : 12641 |
Context : JECA MCA 2024
A computer with a 32 bit wide data bus uses 4k × 8 static RAM memory chips. The smallest memory this computer is
🎥 Video solution / Text Solution of this question is given below:
Each RAM chip = $4k \times 8 = 32k$ bits = 4 KB.
Bus width = 32 bits, each chip = 8 bits → need 4 chips in parallel.
Total memory = $4 \times 4$ KB = 16 KB.
Answer = (B) 16 kb
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