Question Id : 12861 |
Context : JEE Main 2022 (24 June Evening Shift)
If the shortest distance between the lines $\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{\lambda}$ and $\dfrac{x-2}{1} = \dfrac{y-4}{4} = \dfrac{z-5}{5}$ is $\dfrac{1}{\sqrt{3}}$, then the sum of all possible values of $\lambda$ is:
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