Question Id : 13158 |
Context : JEE Main 2022 (29 July Evening Shift)
Let $\vec{a},\vec{b},\vec{c}$ be three coplanar concurrent vectors such that the angles between any two of them are the same. If the product of their magnitudes is $14$ and
$
(\vec{a}\times\vec{b})\cdot(\vec{b}\times\vec{c})
+(\vec{b}\times\vec{c})\cdot(\vec{c}\times\vec{a})
+(\vec{c}\times\vec{a})\cdot(\vec{a}\times\vec{b})=168,
$
then $|\vec{a}|+|\vec{b}|+|\vec{c}|$ is equal to:
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