Question Id : 13238 |
Context : JEE Main 2023 (29 January Evening Shift)
Let $y=y(x)$ be the solution of the differential equation
$$x\log_e x \,\frac{dy}{dx}+y=x^2\log_e x,\quad (x>1).$$
If $y(2)=2$, then $y(e)$ is equal to:
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