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Question Id : 13255 | Context : JEE Main 2023 (30 January Morning Shift)
Let the system of linear equations \[ \begin{cases} x + y + kz = 2,\\ 2x + 3y - z = 1,\\ 3x + 4y + 2z = k \end{cases} \] have infinitely many solutions. Then the system \[ \begin{cases} (k+1)x + (2k-1)y = 7,\\ (2k+1)x + (k+5)y = 10 \end{cases} \] has:


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