Question Id : 13255 |
Context : JEE Main 2023 (30 January Morning Shift)
Let the system of linear equations
\[
\begin{cases}
x + y + kz = 2,\\
2x + 3y - z = 1,\\
3x + 4y + 2z = k
\end{cases}
\]
have infinitely many solutions. Then the system
\[
\begin{cases}
(k+1)x + (2k-1)y = 7,\\
(2k+1)x + (k+5)y = 10
\end{cases}
\]
has:
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