Question Id : 13477 |
Context : JEE Main 2023 (13 April Evening Shift)
Let $|\vec a|=2$, $|\vec b|=3$ and the angle between the vectors $\vec a$ and $\vec b$ be $\dfrac{\pi}{4}$. Then $|(\vec a+2\vec b)\times(2\vec a-3\vec b)|^2$ is equal to:
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