If $|\alpha^2| = 4$ and $-3 \le \lambda \le 2$, then the range of $|\lambda \alpha^2|$ is……
🎥 Video solution / Text Solution of this question is given below:
Given $|\alpha^2| = 4$ and $-3 \le \lambda \le 2$.
Then $|\lambda \alpha^2| = 4|\lambda|$.
Minimum value at $\lambda = 0$ → 0.
Maximum value at $\lambda = -3$ → $4 \times 3 = 12$.
Hence, range is $[0, 12]$.
$\boxed{\text{Answer: (C) } [0, 12]}$