Question Id : 14165 |
Context : JEE Main 2024 (29 January Morning Shift)
For $x\in\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)$, if
$y(x)=\displaystyle\int \frac{\csc x+\sin x}{\csc x\sec x+\tan x\sin^2 x}\,dx$,
and $\displaystyle\lim_{x\to \left(\frac{\pi}{2}\right)} y(x)=0$, then $y\!\left(\dfrac{\pi}{4}\right)$ is equal to:
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