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Question Id : 14199 | Context : JEE Main 2024 (30 January Morning Shift)
Let $(\alpha,\beta,\gamma)$ be the foot of the perpendicular from the point $(1,2,3)$ on the line \[ \frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}. \] Then $19(\alpha+\beta+\gamma)$ is equal to:


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