Question Id : 14468 |
Context : JEE Main 2024 (8 April Morning Shift)
Let $I(x)=\displaystyle\int \frac{6}{\sin^{2}x,(1-\cot x)^{2}},dx$. If $I(0)=3$, then $I!\left(\tfrac{\pi}{12}\right)$ is equal to
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