Question Id : 14818 |
Context : JEE Main 2025 (3 April Evening Shift)
Let $y=y(x)$ be the solution of the differential equation $\dfrac{dy}{dx}+3\tan^2 x,y+3y=\sec^2 x$, $y(0)=\dfrac{1}{3}+e^3$. Then $y!\left(\dfrac{\pi}{4}\right)$ is equal to:
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