Question Id : 15011 |
Context : UGC NET Computer Science 26 June 2025 (Paper II)
What is the total swap time (Swap in & Swap out) in a system for a 15 MB process with a transfer rate of 30 MBps.
Given that there is an average latency of 12 ms, however no head seeks involved.
🎥 Video solution / Text Solution of this question is given below:
Total swap time = 2 × (Transfer time + Latency)
Transfer time for 15 MB = 15 / 30 = 0.5 sec
So,
Total time = 2 × (0.5 + 0.012) = 1.024 sec