JEE Main 2019 (9 January Morning Shift)

Question

For any $	heta \in \left(\frac{\pi}{4}, \frac{\pi}{2}ight)$, the expression $3(\cos 	heta - \sin 	heta)^4 + 6(\sin 	heta + \cos 	heta)^2 + 4\sin^6 	heta$ equals:

Accepted Answer

$13 - 4\cos^6 	heta$

Answer

$13 - 4\cos^2 	heta + 6\sin^2 	heta \cos^2 	heta$

Answer

$13 - 4\cos^2 	heta + 6\cos^2 	heta$

Answer

$13 - 4\cos^4 	heta + 2\sin^2 	heta \cos^2 	heta$

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