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Question Id : 15554 | Context : JEE Main 2019 (9 January Morning Shift)
If $y=y(x)$ is the solution of the differential equation $x\dfrac{dy}{dx}+2y=x^{2}$, satisfying $y(1)=1$, then $y\!\left(\dfrac{1}{2}\right)$ is equal to:

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