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Question Id : 15958 | Context : JEE Main 2018 (16 April Morning Shift)
If the function $f$ defined as $f(x) = \dfrac{1}{x} - \dfrac{kx - 1}{e^{2x} - 1}, ; x \ne 0$, is continuous at $x = 0$, then the ordered pair $(k, f(0))$ is equal to :

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