Question Id : 16076 |
Context : JEE Main 2016 (9 April Morning Shift)
The shortest distance between the lines
$\dfrac{x}{2} = \dfrac{y}{2} = \dfrac{z}{1}$
and
$\dfrac{x + 2}{-1} = \dfrac{y - 4}{8} = \dfrac{z - 5}{4}$
lies in the interval:
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