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Question Id : 16076 | Context : JEE Main 2016 (9 April Morning Shift)
The shortest distance between the lines $\dfrac{x}{2} = \dfrac{y}{2} = \dfrac{z}{1}$ and $\dfrac{x + 2}{-1} = \dfrac{y - 4}{8} = \dfrac{z - 5}{4}$ lies in the interval:


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