The integral $\int e^x (1+\tan x)\sec x , dx$ equals
🎥 Video solution / Text Solution of this question is given below:
$ e^x (1+\tan x)\sec x = e^x (\sec x + \sec x \tan x) $
Let $f(x)=\sec x$, then $f'(x)=\sec x \tan x$
$ \Rightarrow \int e^x [f(x)+f'(x)] dx = e^x f(x) + C $
$ = e^x \sec x + C $