[Video Solution] (sin−1x)2−(cos−1x)2=a,0<x<1,a;=0 then the value of 2x2−12x^2 - 12x2−1 is: | ASPIRE STUDY

Name: [Video Solution] (sin−1x)2−(cos−1x)2=a,0<x<1,a;=0 then the value of 2x2−12x^2 - 12x2−1 is: | ASPIRE STUDY
Uploaded: 2026-10-03T03:28:15+00:00
Description: (sin−1x)2−(cos−1x)2=a,0<x<1,a;=0 then the value of 2x2−12x^2 - 12x2−1 is: | Watch the step-by-step video solution for this NIMCET PYQ.

(sin−1x)2−(cos−1x)2=a,0<x<1,a;=0 then the value of 2x2−12x^2 - 12x2−1 is: | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-10-03T03:28:15+00:00 Thumbnail: Open Page: https://www.aspirediary.com/library/video/12608/sin-1x-2-cos-1x-2-a-0-x-1-a-0-then-the-value-of-2x2-12x-2-12x2-1-is

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