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Let f be a non-negative function in [0, 1] and twice differentiable in (0, 1). If ∫_0^x √ 1 - (f'(t))^2 dt = ∫_0^x f(t)dt , 0 \le x \le 1 and f(0) = 0, then \mathop \lim \limits_x \to 0 1 \over x^2∫_0^x f(t)dt : | Watch the step-by-step video solution for this NIMCET PYQ.