[Video Solution] \textIf 0 < x < \tfrac1√2 \text and \tfrac\sin^-1xα = \tfrac\cos^-1xβ, \tex... | ASPIRE STUDY

Name: [Video Solution] \textIf 0 < x < \tfrac1√2 \text and \tfrac\sin^-1xα = \tfrac\cos^-1xβ, \tex... | ASPIRE STUDY
Uploaded: 2026-02-15T10:07:32+00:00
Description: \textIf 0 < x < \tfrac1√2 \text and \tfrac\sin^-1xα = \tfrac\cos^-1xβ, \text then the value of \sin!\left(\tfrac2παα+β\right) \text is : | Watch the step-by-step video solution for this NIMCET PYQ.

\textIf 0 < x < \tfrac1√2 \text and \tfrac\sin^-1xα = \tfrac\cos^-1xβ, \text then the value of \sin!\left(\tfrac2παα+β\right) \text is : | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-02-15T10:07:32+00:00 Thumbnail: Open Page: https://www.aspirediary.com/library/video/13070/textif-0-x-tfrac1-2-text-and-tfrac-sin-1x-tfrac-cos-1x-tex

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