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Let A = [a_ij]_2* 2, where a_ij\ne 0 for all i,j and A^2=I. Let a be the sum of all diagonal elements of A and b=\lvert A\rvert (i.e., b=\det A). Then 3a^2+4b^2 is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.