[Video Solution] \mathrma, \mathrmb>0, let f(x)= \begincases\frac\tan ((\mathrma+1) x)+\mathrm... | ASPIRE STUDY

\mathrma, \mathrmb>0, let f(x)= \begincases\frac\tan ((\mathrma+1) x)+\mathrmb \tan xx, & x< 0 \\ 3, & x=0 \\ \frac√\mathrma x+\mathrmb^2 x^2-√\mathrma x\mathrm~b √\mathrma x √x, & x> 0\endcases be a continuous function at x=0. Then \frac\mathrmb\mathrma is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.