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Let f:\mathbbR\to\mathbbR be a twice differentiable function such that f(2)=1. If F(x)=x f(x) for all x\in\mathbbR, \displaystyle∫_0^2 x F''(x),dx=6 and \displaystyle∫_0^2 x^2 F''(x),dx=40, then F'(2)+\displaystyle∫_0^2 F(x),dx is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.