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Consider two vectors \vecu=3\hati-\hatj and \vecv=2\hati+\hatj-\lambda\hatk,\ \lambda>0. The angle between them is given by \cos^-1!\left(\dfrac√52√7\right). Let \vecv=\vecv_1+\vecv_2, where \vecv_1 is parallel to \vecu and \vecv_2 is perpendicular to \vecu. Then the value \left|\vecv_1\right|^2+... | Watch the step-by-step video solution for this NIMCET PYQ.