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Let f:[0,1]\to\mathbbR be such that f(xy)=f(x)\,f(y) for all x,y\in[0,1], and f(0)\ne 0. If y=v(x) satisfies the differential equation \dfracdydx=f(x) with y(0)=1, then y\!\left(\dfrac14\right)+y\!\left(\dfrac34\right) is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.