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If the function f defined on \left(\dfracπ6, \dfracπ3\right) by f(x) = \begincases \dfrac√2\cos x - 1\cot x - 1, & x \ne \dfracπ4 \ k, & x = \dfracπ4 \endcases is continuous, then k is equal to | Watch the step-by-step video solution for this NIMCET PYQ.