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If 2\displaystyle∫_0^1 \tan^-1 x , dx = \displaystyle∫_0^1 \cot^-1 (1 - x + x^2) , dx, then \displaystyle∫_0^1 \tan^-1 (1 - x + x^2) , dx is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.