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Let PQR be a triangle such that \overrightarrowPQ = -2\hati - \hatj + 2\hatk and \overrightarrowPR = a\hati + b\hatj - 4\hatk,; a, b \in \mathbbZ . Let S be the point on QR , which is equidistant from the lines PQ and PR . If |PR| = 9 and \overrightarrowPS = \hati - 7\hatj + 2\hatk ... | Watch the step-by-step video solution for this NIMCET PYQ.