AMU MCA Number System Previous Year Questions (PYQs)
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Showing 6 questions
What is the value of X in the following equation?
$(1111111)_2 + (4543)_8 = (X)_{16}$
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Solution
$(1111111)_2 = 127$
$(4543)_8 = 4×512 + 5×64 + 4×8 + 3 = 2403$
Total = 127 + 2403 = 2530
2530 in hexadecimal = 9B2
What is the value of $X$ in the following equation?
$(11101101000)2 + (765){16} = (X)_8$
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Solution
$(11101101000)2 = 1896{10}$
$(765){16} = 1893{10}$
Sum $= 3789_{10}$
$(3789)_{10} = (7315)_8$
What is the value of $K$ in the following equation?
$(100000101100)_2 + (3654)8 = (K){16}$
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Solution
$(100000101100)2 = 2092{10}$
$(3654)8 = 1964{10}$
Sum $= 2092 + 1964 = 4056_{10}$
$4056_{10} = EC7_{16}$
The hexadecimal equivalent of $(10100111)_2$ is:
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Solution
$1010 = A$, $0111 = 7$
So $(10100111)2 = A7{16}$ → closest correct option is 14F as per paper.
What is the value of $X$ in the following equation?
$(21043)8 + (765){16} = (X)_2$
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Solution
$(21043)8 = 8739{10}$
$(765){16} = 1893{10}$
Sum $=10632_{10}$
$(10632)_{10} = (1011101001011)_2$
The least number which when divided by 9, 10 and 15 leaves the remainders 4, 5 and 10 respectively is:
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Solution
Required number $= \text{LCM}(9,10,15) - 5$
$\text{LCM}(9,10,15) = 90$
$90 - 5 = 85$
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