Aspire Faculty ID #16837 · Topic: AMU MCA 2024 · Just now
AMU MCA 2024

The least number which when divided by 9, 10 and 15 leaves the remainders 4, 5 and 10 respectively is:

Solution

Required number $= \text{LCM}(9,10,15) - 5$ $\text{LCM}(9,10,15) = 90$ $90 - 5 = 85$

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