Aspire Faculty ID #15110 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

The equation of straight line passing through (3, 2) and perpendicular to $y = x$ is

Solution

Slope of $y = x$ is 1 → perpendicular slope = −1. Equation: $y - 2 = -1(x - 3) \Rightarrow x + y = 5$.
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